Any number is a combination of digits, like 342 have three digits and 4325 have four digits. For calculating the digits of any number user have three possibilities to input values.
- Enter +ve numbers
- Enter -ve numbers
- Enter zero
This code is correct when user enter +ve numbers Only.
Example
#include<iostream.h> #include<conio.h> void main() { int no,a=0; clrscr(); cout<<"Enter any num : "; cin>>no; while(no>0) { no=no/10; a++; } cout<<"\n no. of digits in given number is: "<<a; getch(); }
Output
Enter any num : 650 no. of digits in given number is : 3
This code is satisfy all the above three conditons.
C++ program to count number of digits of an integer
#include<iostream.h> #include<conio.h> void main() { int no,a=0; clrscr(); cout<<"Enter any num : "; cin>>no; if(no<0) { no=no * -1; } else if(no==0) { no=1; } while(no>0) { no=no/10; a++; } cout<<"\n no. of digits in given number is: "<<a; getch(); }
Output
Enter any num : -650 no. of digits in given number is : 3
